Convolution Command: Inputs Invalid

1 回表示 (過去 30 日間)
Andrew Cunningham
Andrew Cunningham 2018 年 9 月 23 日
コメント済み: Andrew Cunningham 2018 年 9 月 27 日
I am having trouble getting the output of my two functions to be accepted by the convolution function. Any help is appreciated getting this to work. I get the following when I use conv: Invalid data type. First and second arguments must be numeric or logical. I am familiar with matlab and can do the plots and other aspects once I get the function working. Thank you in advance for any help. I attached my code below:
t = -5:10; syms n x1 = symsum(dirac(t-8.*n),n,0,5); h1 = exp(-t).*heaviside(t); H1 = h1.'; Yt = conv(x1,h1);
My two functions are: x(t)=Sum(from 0-5) dirac(t-8n) h(t)=e^(-t)*u(t)
where u(t) is the step function
  2 件のコメント
Image Analyst
Image Analyst 2018 年 9 月 23 日
Why are you using symbolic variables? Can't you just use numerical values with actual values for the elements?
Andrew Cunningham
Andrew Cunningham 2018 年 9 月 23 日
I have “syms n” because it is needed in order to use the symsum to do summation. Cause n is also only from 0 to 5 while the time plot needs to be larger to plot the convolution of the two functions

サインインしてコメントする。

採用された回答

Viren Gupta
Viren Gupta 2018 年 9 月 27 日
I tried relicating your code. x1 is of type sym. You can convert x1 into numeric type using double(x1). That should solve the error. 'h1' is already a numeric type variable
  1 件のコメント
Andrew Cunningham
Andrew Cunningham 2018 年 9 月 27 日
Awesome thanks! I checked it out and that works. I solved it another way though and used ~isfinite(array) which turned the array into finite values. The only values in the array were infinity and 0 so I lost no data in doing it this way. Thank you for the help!

サインインしてコメントする。

その他の回答 (0 件)

カテゴリ

Help Center および File ExchangeAssumptions についてさらに検索

製品


リリース

R2017b

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by