Low pass filter returns NAN

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Kiran Gawas
Kiran Gawas 2012 年 6 月 25 日
hi, I'm trying to use a Low pass filter for my signal data. I have following code for the same
CutF = 25
step = 0.001
fNorm=CutF/(1/(2*step));
[b,a]=butter(10,fNorm,'low');
C1=filtfilt(b,a,Data(:,(i-1)*6+1));
Now this works for some of my data set but for some it returns NAN. I cant figure out why it works in some case and not in others.
thanks in advance
  2 件のコメント
Honglei Chen
Honglei Chen 2012 年 6 月 25 日
Did you check if your input contains NaN?
the cyclist
the cyclist 2012 年 6 月 25 日
Would it be possible for you to include a very small example of "Data" that will allow us to run your code, and exhibits the problem?

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Jan
Jan 2012 年 6 月 26 日
The algorithms of filter and filtfilt do not contain magic sources of NaNs. I'd be very surprised, if the NaNs do not exist in the inputs already, or at least Infs. Test this:
all(isfinite(Data(:))
  1 件のコメント
Cameron
Cameron 2013 年 3 月 3 日
You are not the only one with this problem see link below

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