Typecasting a matrix of 200x8 uint8 to double
34 ビュー (過去 30 日間)
古いコメントを表示
I am typecasting data from uint8 to double so I am using typecast function. I have matrix of 200x8 uint8 which want to convert it into double. So if I use a for loop like below.
if true
convert_double = [];
a = [200x8];
for i =1:200
convert_double = [convert_double; typecast(uint8(a(i,:)), 'double')];
end
end
But I want to remove this for loop so that in one instance itself I will get 200x1 double data
0 件のコメント
回答 (2 件)
Guillaume
2018 年 9 月 18 日
Transpose your a before reshaping into a vector:
convert_double = typecast(reshape(uint8(a'), 1, []), 'double')
0 件のコメント
Christopher Wallace
2018 年 9 月 18 日
double(a);
2 件のコメント
Christopher Wallace
2018 年 9 月 18 日
Absolutely, depends on what the author wants to do with the data. After seeing your answer I see what the "200x1 double data" portion was aiming at.
参考
カテゴリ
Help Center および File Exchange で Logical についてさらに検索
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!