Comparing elements in one matrix in a loop

Hi All,

I have a large matrix with one column containing only values. I want to make a loop and compare every time if the average of 2nd and 1st value is < than a predifined value. When the average of i and j value is > than the predifined value, to show as a result i and j. Thanks in advance!

Answer 1

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A=randi(30,20,1); %Random Matrix for Example
th=12; %Some Predefined value
[rows colm]=size(A);
for i=1:rows-1
     c=(A(i,1)+A(i+1,1))/2;
if c > th
     fprintf('The i is: %d and the next row i+1 value is: %d \n',i,i+1);
     break;
end 
end

[KALYAN ACHARJYA]

The matrix you said having 1 column, so j value always 1.

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What are i and j, as you are assuming?

Look at here for cell array

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Next position is i+1, why j?

Array having length, matrix has size, confirm?

Check my answer, it works as per your defined question (matrix case).

Anyway I am ready to help if I can

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In My Example A is 20x1 Double, check the following-

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Check I have edited the answer. You want to find all positions or the first one only? Like the following?

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The first one only case. I have edited the answer, the added break statement. Please check.

Other c condition also possible, can you clarify more.