How to make a polar plot function curve and not rigid?
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Hello,
I'm not sure why but when I polarplot the graph is very rigid. does anyone know how to change it? I attached a picture and below is what i'm using;
theta = 0*pi: 0.1*pi: 2*pi;
r = 5*cos(4*theta);
polarplot(theta, r)
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回答 (1 件)
Amir Xz
2018 年 9 月 13 日
Steps are so large.
theta = 0*pi: 0.01: 2*pi;
2 件のコメント
Walter Roberson
2018 年 9 月 14 日
0*pi: 0.1*pi: 2*pi is only 21 points, and it needs to cover all 8 nodes in that, so it averages less than 3 points per node. You need to use samples that are closer together, or else you need to interpolate between those 21 points (which could give you a quite misleading idea of what the curve looks like.)
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