# automatically create a group of same elements from an array

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Surya Putra Kartolo 2018 年 8 月 29 日

hello, i have a question about how to automatically group same elements of an array. Example: A=(3,3,3,2,1,4,5,5)
i want to group it into: Group1=(1) Group2=(2) Group3=(3,3,3) Group4=(4) Group5=(5,5)
but sometimes, the elements can be varied and it depends on the calculation. So the number of groups cannot be determined manually. So may i ask your idea, how to make the group automatically based on A ,using for loop?

#### 2 件のコメント

Geoff Hayes 2018 年 8 月 29 日
Surya - please clarify what you mean by the elements can be varied and it depends on the calculation. Also, are you elements always integers?
Surya Putra Kartolo 2018 年 8 月 29 日
yeah, its always integers. i mean is that the integers in A can change depends on the calculation of the image. so sometimes A=(3,3,3,2,1,4,5,5), and if i do for other calculation A can be like A=(6,6,4,4,3,1,2,2). so the integers can be varied.

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### 回答 (1 件)

KL 2018 年 8 月 29 日
try this,
result =mat2cell(sort(A),1, histcounts(findgroups(A))) %A is your array
Output is a cell array where you have groups separated into columns.

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R2018a

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