i have 2 linear equations 2 unknowns
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b0 = c0+3*c1 b1 = c0-5*c1 unknowns are c0 c1. b0,b1 are non variables which should appear in the solution.
thank you david
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Star Strider
2018 年 8 月 23 日
Using the Symbolic Math Toolbox:
syms b0 b1 c0 c1
Eq1 = b0 == c0+3*c1;
Eq2 = b1 == c0-5*c1;
[c0,c1] = solve(Eq1, Eq2)
produces:
c0 =
(5*b0)/8 + (3*b1)/8
c1 =
b0/8 - b1/8
4 件のコメント
Star Strider
2018 年 8 月 23 日
My pleasure.
If my Answer helped you solve your problem, please Accept it!
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