- ImplicitReceive: The input is always buffered. So, the input value remains the same in a single execution of the runnable, no matter how many times it is used.
- ExplicitReceive: The input is not buffered. So, the input value changes whenever it is used within a single execution of the runnable.
What is the difference between ImplicitReceive and ExplicitReceive in AUTOSAR Code?
144 ビュー (過去 30 日間)
古いコメントを表示
MathWorks Support Team
2018 年 8 月 14 日
編集済み: MathWorks Support Team
2022 年 7 月 28 日
What is the difference when changing DataAccessMode for AUTOSAR inputs between ImplicitReceive and ExplicitReceive?
採用された回答
MathWorks Support Team
2022 年 2 月 21 日
編集済み: MathWorks Support Team
2022 年 7 月 28 日
In the AUTOSAR sense for the RTE, the main difference is the following:
However, when generating code from Simulink, the code for the explicit case can be seen as buffered in the code, as shown in the examples below:
1) ImplicitReceive
/* Model step function for TID1 */
void Runnable_2s(void) /* Sample time: [2.0s, 0.0s] */
{
/* Update for RateTransition: '<Root>/RateTransition' incorporates:
* DiscreteIntegrator: '<Root>/Integrator'
*/
Rte_IrvIWrite_Runnable_2s_IRV1(rtDW.Integrator_DSTATE);
/* Update for DiscreteIntegrator: '<Root>/Integrator' incorporates:
* Inport: '<Root>/In2_2s'
*/
rtDW.Integrator_DSTATE += 2.0 * Rte_IRead_Runnable_2s_ReceivePort_In2();
}
2) ExplicitReceive
/* Model step function for TID1 */
void Runnable_2s(void) /* Sample time: [2.0s, 0.0s] */
{
real_T tmpRead;
/* Inport: '<Root>/In2_2s' */
Rte_Read_ReceivePort_In2(&tmpRead);
/* Update for RateTransition: '<Root>/RateTransition' incorporates:
* DiscreteIntegrator: '<Root>/Integrator'
*/
Rte_IrvIWrite_Runnable_2s_IRV1(rtDW.Integrator_DSTATE);
/* Update for DiscreteIntegrator: '<Root>/Integrator' */
rtDW.Integrator_DSTATE += 2.0 * tmpRead;
}
As it can be observed from the code above, the explicit case can be considered buffered in the sense that "tmpRead" is used in the algorithm instead of direct calls to "Rte_Read".
This is required in order to make code and simulation behaviors match, because, in Simulink, a signal is always buffered, and there is no notion of a signal line changing value in the middle of a time step between downstream blocks reading it.
0 件のコメント
その他の回答 (0 件)
参考
カテゴリ
Help Center および File Exchange で AUTOSAR Calibration and Measurement Data についてさらに検索
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!