random exponential cdf numbers

How could I generate random results from an exponential cumulative distribution function?

Thanks, in advance!

Answer 1

[bym]

mu = 2 % mean of distribution
x = -mu*log(1-rand(1,10));  % ten numbers

[evan lan]

I thought it was the reverse type

mu = 2 % mean of distribution

p=1-exp(-rand(1,10)/mu);

Am I wrong?

[bym]

Well, yes you are. Please see http://en.wikipedia.org/wiki/Inverse_transform_sampling