Remove column in cell data

I have a cell such as

C={};
C{1,1}='A';
C{1,2}='B';
C{1,3}='C';
C{2,1}=[1 0 1;0 0 1;2 1 -1];
C{2,2}=[1 2 -1;-1 0 1;0 1 -1];
C{2,3}=[1 0 -1;-1 0 1;-1 1 -1];
C{3,1}=5/9;
C{3,2}=2/9;
C{3,3}=-1/9;

C =

3×3 cell array

    {'A'       }    {'B'       }    {'C'       }
    {3×3 double}    {3×3 double}    {3×3 double}
    {[  0.5556]}    {[  0.2222]}    {[ -0.1111]}

I want to remove a column which have the value -1<=x>=1 in all of the elements in the matrix at the second row. Such that

C =

3×2 cell array

    {'A'       }    {'B'       }
    {3×3 double}    {3×3 double}
    {[  0.5556]}    {[  0.2222]}

[jonas]

Unclear to me. Do the 3x3 arrays change? Can you highlight the values between -1 and 1 you are referring to?

[KSSV]

C{2,2} also has -1<=x>=1.....isn't it?

[Mohamad Agung Prawira Negara]

What I mean is that all elements of 3x3 arrays (all 9 elements is -1<=x<=1). As for C{2,2}, it has 2 in one of the elements.

[jonas]

So what you mean is that you want to keep columns where at least one element (out of 9) lies outside of the specified bounds?

Answer 1

[jonas]

Try this

B=cellfun(@(x) sum(sum(abs(x)>1)),C(2,:),'uniformoutput',false)
B=cell2mat(B);
C(:,B<1)=[]

C =

3×2 cell array

    {'A'       }    {'B'       }
    {3×3 double}    {3×3 double}
    {[  0.5556]}    {[  0.2222]}

[Mohamad Agung Prawira Negara]

Thanks, this one works for me

[jonas]

No problem! It only works for symmetric bounds. Just so you know.