# Calculate weighted average of a 2D matrix

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Abdul Wahab 2018 年 8 月 7 日
コメント済み: stelios loizidis 2019 年 5 月 23 日
Dear all, I hope all is well. I am working with a 2D Matrix that is 376x481. I would like to calculate the weighted average of this matrix for each row, such that the desired output should be sized 376 X 1. I would greatly appreciate any help with this problem.
Thanks.

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### 採用された回答

James Tursa 2018 年 8 月 7 日
E.g.,
w = 1x481 vector of weights
M = your 376x481 matrix of values
result = sum(M.*w,2) / sum(w);
or
sum(bsxfun(@times,M,w),2) / sum(w);
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Abdul Wahab 2018 年 8 月 8 日
This matrix is populated with a non-dimensional variable (376 rows) and associated time history of 481 hours. So each row is then a representation of how this non-dimensional variable is changing through 481 hours (one column for every hour). This non-dimensional number varies in a specific order where it contains both unique and non-unique values of this non-dimensional variable. I would like to figure out the weight vector of the non-unique and unique values in every row and get the weighted average instead of a simple mean. I hope this provides some more insight into my problem.

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### その他の回答 (1 件)

Thorsten 2018 年 8 月 8 日
X = rand(376, 481);
w = rand(1, size(X, 2));
Xw = bsxfun(@times, X, w);
m = mean(Xw, 2);
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stelios loizidis 2019 年 5 月 23 日
Hello,
I saw the commands you wrote above and I have the following question; I have a matrix e.g
[ 5 3 3 1
3 4 5 2
5 0 0 0
3 4 5 2 ]
For this matrix I have to make a weighted average for each row. That is [5+3+(4/5)*(3+1)] / 4 =16/5. Also, if there is only one number and the rest zero (row 3) the weighted average should be [5+0+0+0]/ 1 =5 and the end we choose the largest weight average. How does this work?

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