How can I plot 2 rings in 3D?

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Stef
Stef 2018 年 8 月 3 日
回答済み: Star Strider 2018 年 8 月 3 日
I want to scatter 2 rings first in 2D and then in 3D. In 2D one circle should lie within the other. In 3D one circle should lie above the other so that a separating hyperplane can be put in between. Does anybody know how to code this in matlab? Should look somehow like this: https://cdn-images-1.medium.com/max/1600/0*ngkO1BblQXnOTcmr.png

採用された回答

Star Strider
Star Strider 2018 年 8 月 3 日
Try this:
The Code
N1 = 200; % Number Of Points In Ring
R1 = 0.25 + 0.2*(rand(1, N1)-0.5); % Random Marker Radii
A1 = linspace(0, 2*pi, N1); % Define Angle Vector
Ring1 = R1.*[cos(A1); sin(A1)]; % Create Ring Coordinates
N2 = 200;
R2 = 0.85 + 0.2*(rand(1, N1)-0.5);
A2 = linspace(0, 2*pi, N1);
Ring2 = R2.*[cos(A1); sin(A1)];
figure
plot(Ring1(1,:), Ring1(2,:), '^b', 'MarkerFaceColor','b')
hold on
plot(Ring2(1,:), Ring2(2,:), 'or', 'MarkerFaceColor','r')
hold off
axis equal
N1 = 200; % Number Of Points In Ring
R1 = 0.25 + 0.2*(rand(1, N1)-0.5); % Random Marker Radii
Z1 = 0.10 + 0.2*(rand(1, N1)-0.5); % Random Z-Values
A1 = linspace(0, 2*pi, N1); % Define Angle Vector
Ring1 = R1.*[cos(A1); sin(A1)]; % Create Ring Coordinates
N2 = 200;
R2 = 0.85 + 0.2*(rand(1, N1)-0.5);
Z2 = 0.80 + 0.2*(rand(1, N1)-0.5);
A2 = linspace(0, 2*pi, N1);
Ring2 = R2.*[cos(A1); sin(A1)];
figure
plot3(Ring1(1,:), Ring1(2,:), Z1, '^b', 'MarkerFaceColor','b')
hold on
plot3(Ring2(1,:), Ring2(2,:), Z2, 'or', 'MarkerFaceColor','r')
hold off
axis equal
grid on
You will probably need to tweak this a bit to get the result you want. See the documentation for the plot (link) and plot3 (linked to at the end of that page) functions to discover all their options.
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