Hey all,
Suppose you have as input: matrix A = [10 9 8] and some factor X = 3
As output i would like to obtain: R = [10 10 10 9 9 9 8 8 8]
I am wondering if there are better (faster) solutions then my solution below:
R = zeros(1,length(A)*X);
for i =1:X
R(1+length(A)*(i-1):1:length(A)*i) = A(i);
end

 採用された回答

Fangjun Jiang
Fangjun Jiang 2018 年 8 月 3 日
編集済み: Fangjun Jiang 2018 年 8 月 3 日

1 投票

reshape(repmat(A,X,1),1,[])

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