Have 3 random variables, but need to plot in two dimensions.
Here is the function.
f=1+2*r1*cos(omega)+2*r2*cos(2*omega).
X axis: r1 [-1,1]
Y axis: r2 [-1,1]
Plot the contour which makes f>=0 for all omegas. In other words, plot the contour which makes the minimum value of f is 0.
Apparently, (-0.5,0), (0.5,0), (0,0.5), (0,-0.5) are four points on the contour.
Thanks in advance.

3 件のコメント

Walter Roberson
Walter Roberson 2012 年 6 月 14 日
You are only plotting against r1 and r2: since f>=0 for all omega there is no point plotting the values of omega, just whether f>=0 for all (r1,r2,:) locations.
Xu
Xu 2012 年 6 月 15 日
Yes, you are absolutely right. That's what I asked. I said "plot in two dimensions r1 for x axis and r2 for y axis".
I need to find (r1, r2) which can make fmin=0;
For example, for (r1, r2)=(0.5, 0), f=1+cos(omega), fmin=0 obviously.
Walter Roberson
Walter Roberson 2012 年 6 月 15 日
hints:
ndgrid()
bsxfun()
all()
contour()

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2012 年 6 月 14 日

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