Area of a triangle
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Dr. Seis
2012 年 6 月 14 日
How about polyarea?
>> x = [0, 0, 4];
>> y = [0, 3, 0];
>> area1 = polyarea(x,y)
area1 =
6
>> area2 = 0.5*3*4
area2 =
6
5 件のコメント
Dr. Seis
2012 年 6 月 22 日
I think you would have to do some sort of coordinate transform (to still use the "polyarea" function above), such that all the coordinate values for one of the dimensions (e.g., the z-coordinate) are 0. But it seems using Heron's algorithm would be much easier.
その他の回答 (1 件)
AYUSH MISHRA
2020 年 5 月 26 日
function area=tri_area(b,h,n)
area=0.5*b*h*n;
end
%Here b=base of triangle , h=height of triangle , n=number of triangle
Example
area= tri_area(2,3,5)
area =
15
0 件のコメント
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