How to preallocate to decrease run time?

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Bixius
Bixius 2018 年 7 月 18 日
回答済み: Greg 2018 年 7 月 19 日
Re_1, Re_6, etc.. are have different dimensions i.e. Re_1 = 5000:20000, Re_6 = 200:10000, etc. I wrote this for loop to get the mean values at each value for Reynolds number. How can I preallocate this?
tot_Re = [Re_1 Re_6 Re_8 Re_9 Re_12 Re_13];
tot_Nu = [Nu_1 Nu_6 Nu_8 Nu_9 Nu_12 Nu_13];
Re_mean = 1:max(tot_Re);
for i = 1:max(tot_Re)
k = find(tot_Re == i);
Nu_mean(i) = mean(tot_Nu(k));
end

採用された回答

Greg
Greg 2018 年 7 月 19 日
You can use unique to make your loop more robust. Then, logical indexing is much better than the find you've included. In fact, the find is completely unnecessary.
tot_Re = [Re_1 Re_6 Re_8 Re_9 Re_12 Re_13];
tot_Nu = [Nu_1 Nu_6 Nu_8 Nu_9 Nu_12 Nu_13];
Re_mean = 1:max(tot_Re); % You never use this...
[~,ind,~] = unique(tot_Re); % Using unique allows for gaps in values of tot_Re
Nu_mean = NaN(size(ind)); % Pre-allocate Nu_mean
for lp = 1:length(ind)
k = tot_Re == tot_Re(ind(lp)); % Leave indices as logicals
Nu_mean(lp) = mean(tot_Nu(k));
end

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