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How can I open a file to be read, from a relative file location?

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Connor Sherod
Connor Sherod 2018 年 7 月 10 日
編集済み: Yash Trivedi 2018 年 7 月 10 日
The function which reads from the text file is located at:
C:\Users\x\x\x\MatlabFiles\Connor_Matlab
and it needs to open:
%C:\Users\x\x\x\OUTPUT\Square\M1CR100S4\(AllFld_SVE).OALLFLD
Right now I've tried the relative path. I cannot write it as an absolute path, as it needs to be opened on multiple different computers.
fID = fopen('..\OUTPUT\Square\M1CR100S4\(AllFld_SVE).OALLFLD','r');

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Yash Trivedi
Yash Trivedi 2018 年 7 月 10 日
Hi Connor,
According to the relative path in your fopen() call, you need to go one level higher up in the directory hierarchy.
fID = fopen('..\..\OUTPUT\Square\M1CR100S4\(AllFld_SVE).OALLFLD','r') should work.
A single .. will look for the 'OUTPUT' folder in the 'MatlabFiles' folder and not in the last 'x' folder.
  2 件のコメント
Connor Sherod
Connor Sherod 2018 年 7 月 10 日
Thank you!
So if I had the file located 4 folders back would I need to repeat that 4 times and then proceed from there? Essentially the '..\' acts as taking it back a single step?
Yash Trivedi
Yash Trivedi 2018 年 7 月 10 日
編集済み: Yash Trivedi 2018 年 7 月 10 日
Yes, that's right. The '..\' acts as taking it back a single step. You might want to read through this thread which suggests alternatives and potential pitfalls with relative paths, especially if you're going up four levels of hierarchy -

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