Display question about transparent intersected surfaces

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Hao Li
Hao Li 2018 年 7 月 10 日
回答済み: Hao Li 2018 年 7 月 13 日
Why when I set the intersected surfaces' transparent with 'FaceAlpha', the intersected regions display invalid.
Code:
x=[0:0.01:3];
y=[0:0.01:5];
[X,Y]=meshgrid(x,y);
Z1=X*1.1+Y*1;
Z2=X+Y*1.1;
mesh(X,Y,Z1,'FaceColor','b','EdgeAlpha',0,'FaceAlpha',0.5)
hold on
mesh(X,Y,Z2,'FaceColor','r','EdgeAlpha',0,'FaceAlpha',0.5)
The figure
  3 件のコメント
Jan
Jan 2018 年 7 月 10 日
Which Matlab version are you using? Is OpenGL set to hardware or software?
I can reproduce this effect with Matlab online.
Hao Li
Hao Li 2018 年 7 月 10 日
Thanks for your answer. The version is matlab R2018a, the OpenGL was set to hardware. If I set OpenGL to software, the front and back relationship is wrong, the figure :

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採用された回答

Wentao Du
Wentao Du 2018 年 7 月 13 日
This issue is due to the Order Independent Transparency method used by MATLAB called "Depth Peeling." Unfortunately, there are no existing workarounds.
Changing to "opengl" setting to "hardwarebasic" gives a slightly better result, as this triggers the transparency to use an "object sort" method (Typically this is worse than any Order Independent Transparency method). Or you may use the "painters" renderer for the figures created by executing the following:
>> set(gcf,'Renderer','painters');
Our development team is looking into addressing this issue and it will be considered for a future release of MATLAB.

その他の回答 (1 件)

Hao Li
Hao Li 2018 年 7 月 13 日
Thanks a lot for your answer. Yes, when I set the 'renderer' as 'painter' the figure is better.

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