How to make a FOR loop to be efficient

7 ビュー (過去 30 日間)
Jung 2012 年 6 月 11 日
I have a code that looks something like this.
tol = 1e-16;
a=1; b=500*pi; % b can be larger
pts = a:pi:b;
fx = @(x) besselj(0,x); % or some other function
for i=1:size(pts)-1
[result,err] = somefun(fx,pts(i),pts(i+1)); %or some other function with the sub-intervals as scalar inputs.
end % for loop
Problem is that this type of logic takes a long time to converge. Is there a way to vectorize this loop? Modifying somefun.m itself is not really an option since they could be built-in functions.
Thanks, Jung.
  2 件のコメント
Jung 2012 年 6 月 12 日
pi = 3.1416....


回答 (5 件)

Sean de Wolski
Sean de Wolski 2012 年 6 月 11 日
ans = 4.4409e-16
1e-16 is going to be a hard target to hit... Why not use a realistic tolerance?
  1 件のコメント
Geoff 2012 年 6 月 12 日
Hmmm let me count the number of times over the past 20 years that I've needed a double-precision accuracy of one in ten quadrillion........... I would say it's approximately floor(1e-16).


Mike Hosea
Mike Hosea 2012 年 6 月 12 日
There is no way to do what you ask, and it would not help you much if there were. What is it that that you're really trying to do?

Jung 2012 年 6 月 12 日
Hi Mike,
My ultimate goal is to run a loop more efficiently - i.e. less number of iterations. The code is actually overly simplified since the original code is a bit too long. But essentially, I need to run quad (or some other function with the sub-interval endpoints as scalars) for each of the interval in 1:pi:500*pi (interval could be shorter or significantly longer). I've edited the original posting above to hopefully make it clearer.
Thanks, Jung
  4 件のコメント
Mike Hosea
Mike Hosea 2012 年 6 月 13 日
The nature of "somefun" is critical. If it's numerical integration and the integrand is smooth, you could use a high-order Gaussian quadrature rule, evaluate the function at each node with column j corresponding to pts(j) <= x <= pts(j+1), and do the bulk of the work in one matrix multiplication. This is obviously not an adaptive scheme, but there is a symbolic toolbox function that will calculate Gauss-Legendre nodes and weights, so you can go as high in order as you want (provided you have the memory for the resulting matrix of function evaluations). There are also various strategies you could employ to estimate the error.


newbie traveller
newbie traveller 2012 年 6 月 12 日
if you have GPU (graphics Processing Unit ) then you can use them to compute the calculation in the for loop....check that whether the work that you are doing in the for loop is independent data or not!!i mean independent means one data is not dependent on the calculation of other data.....check that or you can also use the cores of the CPU or labs can see on the command "open matlabpool" to get idea from this this actually helps you to use all of your cores or lab in the the computation time will be reduced to a great extent and remember the command for PCT(parallel computing toolbox) the for will be changed and you will have to use 'parfor'..........clear enough?
  1 件のコメント
Jung 2012 年 6 月 12 日
we do have parallel toolbox and have tried parfor. but problem here is that not all machines have the toolbox so we can't distribute it to others. i've also tried building a stand'alone .exe, but people need to tinker with the code so that's a no-go either.


Ryan 2012 年 6 月 12 日
Perhaps break this into two separate iterations where the first optimization happens more crudely using parameters spaced more greatly apart, then perform another optimization using more closely spaced parameter values based upon the results of the first loop.

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by