Convert the for loop into while loop.

matrix=[6 3 5; 8 4 6; 2 1 9;7 5 2]
[r,c]=size(matrix);
for Row=1:r
for Col=1:c
fprintf('Element(%d,%d)=%d.\n',Row,Col,matrix(Row,Col))
end
end

4 件のコメント

Rik
Rik 2018 年 7 月 4 日
Why do you want to convert these for-loops into while-loops? This seems like the perfect place for a for-loop.
Also, you can format your code by selecting your code and clicking the {}Code button.
Biswajit  Jana
Biswajit Jana 2018 年 7 月 4 日
Thanks,i know,I'm just trying to code in while to know the syntax of the given code instead of using for loop what will it be stand in while loop?/
Jan
Jan 2018 年 7 月 4 日
編集済み: Jan 2018 年 7 月 4 日
I hesitate to convert your code directly to a running version with while, because this might be a homework question.
Biswajit  Jana
Biswajit Jana 2018 年 7 月 4 日
Nope not a homework, just trying to do same code in different loops and all,kindly help me out with while.

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回答 (1 件)

Jan
Jan 2018 年 7 月 4 日

1 投票

for i = 1:10
disp(i)
end
is equivalent to:
i = 1;
while i <= 10
disp(i)
i = i + 1;
end

3 件のコメント

Biswajit  Jana
Biswajit Jana 2018 年 7 月 4 日
I know this.I want to do with matrix as given in the question.
Rik
Rik 2018 年 7 月 4 日
This concept should be easy to apply to your case. Why don't you try something and show the result here if it fails?
Jan
Jan 2018 年 7 月 4 日
編集済み: Jan 2018 年 7 月 4 日
@Biswajit Jana: You know how to convert one for loop into a while loop. Your code has two for loops. You can simply copy my example and paste it twice inside each other. Then rename the loop counters and limits. It is not hard. Please try it.

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Jan
2018 年 7 月 4 日

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