how to resample points with preset angle

1 回表示 (過去 30 日間)
BeeTiaw
BeeTiaw 2018 年 6 月 27 日
回答済み: Ameer Hamza 2018 年 6 月 27 日
Hi expert,
I am not sure if the title of this post represents the question I am going to ask very well.
I have the coordinate of a rounded triangle as shown in the plot
The coordinate of the plot is listed below. My question is how to resample this curve suppose I want to have them every theta = 2*pi/37 or every 10 degree spacing.
the x and y coordinate of the triangle is:
0.7900 0
0.7898 0.0816
0.7893 0.1627
0.7883 0.2426
0.7868 0.3211
0.7847 0.3974
0.7819 0.4712
0.7781 0.5420
0.7733 0.6094
0.7672 0.6730
0.7596 0.7325
0.7503 0.7875
0.7391 0.8379
0.7257 0.8834
0.7100 0.9238
0.6917 0.9591
0.6707 0.9892
0.6467 1.0141
0.6197 1.0338
0.5895 1.0484
0.5560 1.0580
0.5191 1.0627
0.4789 1.0627
0.4353 1.0583
0.3885 1.0497
0.3384 1.0371
0.2852 1.0208
0.2291 1.0010
0.1703 0.9782
0.1090 0.9526
0.0454 0.9244
-0.0200 0.8940
-0.0870 0.8616
-0.1553 0.8276
-0.2244 0.7922
-0.2940 0.7557
-0.3637 0.7182
-0.4330 0.6800
-0.5016 0.6414
-0.5690 0.6024
-0.6348 0.5632
-0.6986 0.5240
-0.7600 0.4848
-0.8185 0.4458
-0.8739 0.4071
-0.9258 0.3686
-0.9737 0.3305
-1.0175 0.2926
-1.0569 0.2552
-1.0915 0.2180
-1.1212 0.1812
-1.1458 0.1446
-1.1650 0.1082
-1.1789 0.0721
-1.1872 0.0360
-1.1900 0
-1.1872 -0.0360
-1.1789 -0.0721
-1.1650 -0.1082
-1.1458 -0.1446
-1.1212 -0.1812
-1.0915 -0.2180
-1.0569 -0.2552
-1.0175 -0.2926
-0.9737 -0.3305
-0.9258 -0.3686
-0.8739 -0.4071
-0.8185 -0.4458
-0.7600 -0.4848
-0.6986 -0.5240
-0.6348 -0.5632
-0.5690 -0.6024
-0.5016 -0.6414
-0.4330 -0.6800
-0.3637 -0.7182
-0.2940 -0.7557
-0.2244 -0.7922
-0.1553 -0.8276
-0.0870 -0.8616
-0.0200 -0.8940
0.0454 -0.9244
0.1090 -0.9526
0.1703 -0.9782
0.2291 -1.0010
0.2852 -1.0208
0.3384 -1.0371
0.3885 -1.0497
0.4353 -1.0583
0.4789 -1.0627
0.5191 -1.0627
0.5560 -1.0580
0.5895 -1.0484
0.6197 -1.0338
0.6467 -1.0141
0.6707 -0.9892
0.6917 -0.9591
0.7100 -0.9238
0.7257 -0.8834
0.7391 -0.8379
0.7503 -0.7875
0.7596 -0.7325
0.7672 -0.6730
0.7733 -0.6094
0.7781 -0.5420
0.7819 -0.4712
0.7847 -0.3974
0.7868 -0.3211
0.7883 -0.2426
0.7893 -0.1627
0.7898 -0.0816
0.7900 0

採用された回答

Ameer Hamza
Ameer Hamza 2018 年 6 月 27 日
Try this
x = points(:,1); % first column of points you shared
y = points(:,2); % second column of points
x_new = interp1(linspace(0, 2*pi, numel(x)), x, 0:2*pi/37:2*pi);
y_new = interp1(linspace(0, 2*pi, numel(y)), y, 0:2*pi/37:2*pi);
x_new and y_new contains the required points.

その他の回答 (0 件)

カテゴリ

Help Center および File ExchangeMultirate Signal Processing についてさらに検索

タグ

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by