Hey guys! I wrote a code to study the dynamic of some parameters in a reactor. The problem is that I applied RK, but one of the variables is an explicit equation and, therefore, I'm having trouble to figure it out how to plot the graphic of Tcw2. Can somebody give me an idea? I need Tcw2 versus t (time).....
Thank you! Best regards!
function dx=EstudoDeCaso_RK4(t,x)
%Legenda
%x(1) ---> V
%x(2) ---> h
%x(3) ---> Ca
%x(4) ---> Cb
%x(5) ---> Cc
%x(6) ---> Cd
%x(7) ---> Cw
%x(8) ---> Tr
%Parâmetros
Vu=4; %m³
d=(2*Vu/pi)^(1/3); %m
H=2*d; %m
A=pi*d^2/4; %m²
Vo=0.2; %m³
ve=0.004; %m³/s
Cwe=55; %kmol/m³
Cbe=1; %kmol/m³
Fbe=Cbe*ve*1000; %mol/s
MMa=88/1000; %kg/mol
MMw=18/1000; %kg/mol
MMb=40/1000; %kg/mol
MMmist=(Cbe/(Cbe+Cwe)*MMb+Cwe/(Cbe+Cwe)*MMw); %kg/mol
Cp=75.24; %J/(kmol.K)
Cpa=170.7; %J/(kmol.K)
theta_w=Cwe/Cbe; %(-)
UA=3000; %J/(s.K)
To=300; %K
Tref=273; %K
Tcw1=285; %K
mcw=100; %kg/s
dH=-7.9076E+07; %J/kmol
ko=0.39175; %m³/(kmol.s)
E=5472.7; %K^-1 ----> Ea/R
%Equações Explícitas
Na=x(3)*x(1);
Nb=x(4)*x(1);
Nc=x(5)*x(1);
Nd=x(6)*x(1);
Nw=x(7)*x(1);
NCp=Cp*(Nb+Nc+Nd+Nw)+Cpa*Na;
kd=ko*exp(E*(1/273-1/x(8)));
Kc=10^(3885.44/x(8));
ra=kd*(x(5)*x(6)/Kc-x(3)*x(4));
rb=ra;
rc=kd*(x(3)*x(4)-x(5)*x(6)/Kc);
rd=rc;
Tcw2=x(8)-(x(8)-Tcw1)*exp(-UA/(mcw*Cp));
Qdot=mcw*Cp*(Tcw1-x(8))*(1-exp(-UA/(mcw*Cp)));
%Equações Diferenciais
dx(1)=ve;
dx(2)=ve/A;
dx(3)=ra-ve/x(1)*x(3);
dx(4)=rb+ve/x(1)*(Cbe-x(4));
dx(5)=rc-ve/x(1)*x(5);
dx(6)=rd-ve/x(1)*x(6);
dx(7)=ve/x(1)*(Cwe-x(7));
dx(8)=(Qdot-Fbe*Cp*(1+theta_w)*(x(8)-To)-ra*x(1)*dH)/NCp;
%Vetor linha em vetor coluna
dx=dx';
end

回答 (1 件)

Torsten
Torsten 2018 年 6 月 27 日

1 投票

Can you plot Tr versus t ?
Then you should also be able to plot
Tr-(Tr-Tcw1)*exp(-UA/(mcw*Cp))
versus t.
Best wishes
Torsten.

2 件のコメント

Mateus Oliveira Nunes
Mateus Oliveira Nunes 2018 年 6 月 28 日
But could you tell me how? because it isn't working at all
Mateus Oliveira Nunes
Mateus Oliveira Nunes 2018 年 6 月 28 日
I got it! Thank you!

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