numerical derivation of function ?
1 回表示 (過去 30 日間)
古いコメントを表示
how to derivate this function in matlab :
func = q*sin(phi)+r*cos(teta)
where q , r , teta ,phi are functions , how to find the derivative expression like this :
deriv_func =qdot*sin(phi)+phidot*cos(phi)*q +rdot*cos(teta)-tetadot*sin(teta)*r
0 件のコメント
採用された回答
Walter Roberson
2018 年 6 月 20 日
You cannot do that numerically. Numeric differentiation can never return a symbolic result.
With the symbolic toolbox, you would do something like,
syms q(t) r(t) phi(t) teta(t)
func = q*sin(phi)+r*cos(teta)
diff(func, t)
to get
cos(teta(t))*diff(r(t), t) + sin(phi(t))*diff(q(t), t) + cos(phi(t))*q(t)*diff(phi(t), t) - sin(teta(t))*r(t)*diff(teta(t), t)
You indicated that q r phi teta were functions, but you did not indicate what they were functions of, so I assumed they were all functions of t.
その他の回答 (0 件)
参考
製品
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!