How to find the successive difference between timestamps in hours?
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The attachment has 1138 samples of datenum format.I want to find the sum of total hours in this order of index (2-1)+(4-3)+(6-5)+.....+(1138-1137). Any suggestions. The answer comes around 200 hours.
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Guillaume
2018 年 6 月 18 日
d = datetime(yourdatenumvector, 'ConvertFrom', 'datenum'); %convert to the more useful datetime
sum(hours(d(2:2:end) - d(1:2:end)))
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Guillaume
2018 年 6 月 18 日
In R2013a, it could possibly be calculated with:
sum(yourdatenumvector(2:2:end) - yourdatenumvector(1:2:end)) * 24
No guarantee that it works correctly. 2013a is ancient now.
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