How to replace half the number of specific element in an array?

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abdur rauf
abdur rauf 2018 年 6 月 18 日
編集済み: Stephen23 2018 年 6 月 18 日
Hello every one,
I have a row vector having 8236 columns, out of which 863 columns have a value 4. I want to replace 431 of the columns by a value 2. For simplicity, I am giving a vector having only 23 columns
A=[1 2 3 4 4 1 2 4 4 3 4 4 4 2 1 3 4 4 4 2 1 4 4]
Here, in this vector, there are 12 columns having a value 4. How to replace half the columns by a value 2?
Any help will be appreciated.

採用された回答

Stephen23
Stephen23 2018 年 6 月 18 日
編集済み: Stephen23 2018 年 6 月 18 日
To change random columns:
>> A=[1 2 3 4 4 1 2 4 4 3 4 4 4 2 1 3 4 4 4 2 1 4 4]
A =
1 2 3 4 4 1 2 4 4 3 4 4 4 2 1 3 4 4 4 2 1 4 4
>> nnz(A==4)
ans = 12
>> idx = find(A==4);
>> num = numel(idx);
>> A(idx(randperm(num,ceil(num/2)))) = 2
A =
1 2 3 2 2 1 2 4 4 3 2 4 2 2 1 3 2 4 4 2 1 2 4
>> nnz(A==4)
ans = 6

その他の回答 (2 件)

KALYAN ACHARJYA
KALYAN ACHARJYA 2018 年 6 月 18 日
編集済み: KALYAN ACHARJYA 2018 年 6 月 18 日
A=[1 2 3 4 4 1 2 4 4 3 4 4 4 2 1 3 4 4 4 2 1 4 4];
for i=1:length(A)/2;
if A(i)==4
A(i)=2;
end
end

Ameer Hamza
Ameer Hamza 2018 年 6 月 18 日
編集済み: Ameer Hamza 2018 年 6 月 18 日
Here is one possible solution
A=[1 2 3 4 4 1 2 4 4 3 4 4 4 2 1 3 4 4 4 2 1 4 4];
index = find(A==4);
randomIndex = randperm(length(index));
A(index(randomIndex(1:end/2))) = 2;
it will randomly select which columns to change.

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