How do I skip items in a legend?
古いコメントを表示
How do I skip items in legend? Say I have 6 plots with 3 actual values and 3 interpolated curves. I only want to label the actual value curves so
legend('first','','second','','third')
doesn't really work because the interpolated curve still shows.
14 件のコメント
EhsanZ
2018 年 3 月 12 日
1- Select the curve you don't want have legend. 2- Go to the "more properties" (while the curve is still selected). 3- Turn "HandleVisibility" off.
FTil
2018 年 6 月 16 日
Or programmatically:
plot(...,'HandleVisibility','off')
Akash Menon
2018 年 12 月 13 日
figure
h1=histfit(no_ess,20,'gamma');
xlim([0 1])
hold on
h2=histfit(with_ess,50,'kernel');
xlim([0 1])
set(get(get(h1(2),'Annotation'),'LegendInformation'),'IconDisplayStyle','off');
set(get(get(h2(2),'Annotation'),'LegendInformation'),'IconDisplayStyle','off');
legend('MCR SOL','MCR SOL ESS')
Here's a quick sample of how it worked- for my histograms I didn't want the two red lines to be labelled in the legend. I found out that for the histograms- it creates a handle h(1) and (2) where 1 corresponds to the bar charts and 2 to the fitting lines.
Just an example- hope it helps!

neurosock hardcore BCIs
2021 年 1 月 27 日
編集済み: neurosock hardcore BCIs
2021 年 1 月 27 日
The nice thing about 'HandleVisibility' in contrast to 'IconDisplayStyle' is that it can be called directly in the function of plots and patches:
plot(...,'HandleVisibility','off')
patch(...,'HandleVisibility','off')
Dandro18048
2021 年 4 月 6 日
@FTil I was looking exactly for this, thank you very much! Simplest solution of everything that's been posted here.
Giuseppe Degan Di Dieco
2021 年 6 月 15 日
Dear Akash,
thanks for your tip, hope you're still reagind these days.
It really helped me in avoid plotting one of two labels in a stacked bar plot.
Best.
Rik
2021 年 6 月 15 日
@Giuseppe Degan Di Dieco, regarding your flag ("Really helpful, and easy to code because of the set and get commands!"): flags are used to attract the attention of site admins and users with editing privileges. They should not be used as personal bookmarks.
Giuseppe Degan Di Dieco
2021 年 6 月 16 日
Sorry then, if there is a way for removing it, please let me know, and I will amend it.
I will bear in mind for the future.
Best.
Rik
2021 年 6 月 16 日
No problem. I have already removed the flag.
Giuseppe Degan Di Dieco
2021 年 7 月 29 日
Hi Rik,
thanks for your work.
Best.
Christian Busse
2021 年 8 月 19 日
Hello,
the changes made in MATLAB 2021a do not produced expected/desired results. Using
leg = legend('first','second','third')
leg.String(2) = ''
does not skip producing a legend label for the second curve but rather assigns the label 'third' to the second curve.
I couldn't find any hint in the documentation how to actually skip/remove legend labels for particular curves and keep the others as is.
Christian Busse
2021 年 8 月 19 日
Ok this workaround found in the comments below, actually solved my problem:
legend([h1 h3],{'Leg1' 'Leg3'});
Assuming that the line1 and line3 have been assigned to h1 and h3 (h1 = plot(...), h3 = plot(...)), respectively.
Greg Vieira
2021 年 9 月 4 日
How can you do this for multiple plots? For example, I have 1001 data sets plotted and only want the legend to show 1 of the first 1000 plots and the last plot. It is not reasonable for me to place 999 ' ' placeholders.
Kaveh Vejdani
2023 年 6 月 10 日
First plot data1, then data1001, the set L.AutoUpdate = 'off'; % L=Legend
採用された回答
その他の回答 (13 件)
A really good method is to do what's mentioned at https://stackoverflow.com/questions/13685967/how-to-show-legend-for-only-a-specific-subset-of-curves-in-the-plotting.
Essentially set the 'HandleVisibility' attribute to 'off' when plotting something, as such:
plot(x,y,'HandleVisibility','off')
This has some implications concerning interacting with that handle in other ways, but if you don't plan on using the handle, this is a great dynamic way to not include certain plots in your legend. It works especially well when you're plotting iteratively, and don't want to store handles and then hard-code the legend to fit your exact plot.
5 件のコメント
Giuseppe Degan Di Dieco
2021 年 11 月 2 日
Thank you Matt for updating the thread.
Keep in touch for tips sharing and creating a MATLAB users community.
Best.
Michael Van de Graaff
2022 年 1 月 17 日
This was very helpful Matt, thank you
Sebastian Lopez
2022 年 5 月 27 日
Really helpful. Thanks!
Andres Ricardo Herrera Orozco
2024 年 1 月 16 日
Really helpful. Thanks!
Hannah
2024 年 9 月 25 日
Fantastic advice. Thank you.
Walter Roberson
2011 年 1 月 25 日
編集済み: Rik
2022 年 4 月 5 日
27 投票
You can set the IconDisplayStyle to off for the items you do not wish a legend for. See this documentation.
The link above was valid for the documentation from R2012a. The equivalent page in R2022a suggests a different strategy (i.e. only providing the handles to legend for the objects you wish to include). In the current release IconDisplayStyle is documentated under the properties of the graphics primitives (e.g. line objects or patch objects).
Documentation pages from specific releases will remain online for 5 years.
6 件のコメント
Jack Barrett
2011 年 10 月 27 日
this is a much nicer solution. kudos
Danny Smith
2015 年 4 月 27 日
Wow, this solution is much smoother than the other proposed, and more generally applicable.
It allows you to turn off the ones you don't want, rather than having to turn on the ones you do. If you (like me) are plotting many data sets on the same graph, this is much more useful and simple.
If you have the handle for the data set you DON'T want included, all you need is this line:
set(get(get(h,'Annotation'),'LegendInformation'),'IconDisplayStyle','off');
where "h" is changed to the name of your handle.
For more information, follow the link provided by Walter and John.
Tom
2016 年 4 月 22 日
This is the ideal solution for implementing "plot" in a loop where it is difficult to assign a unique handle each iteration. Thank you!
Nuwan Liyanage
2020 年 8 月 25 日
This is really helpful, thanks!
Fernando Zigunov
2021 年 11 月 29 日
broken link!
Tanya Meyer
2022 年 4 月 5 日
Yes - broken link :(
Junette Hsin
2019 年 3 月 21 日
編集済み: Junette Hsin
2019 年 3 月 21 日
25 投票
I ran into this problem and I have not seen this method suggested yet, but I solved it by changing the order of my plotted lines which affects what the legend displays (I am using MATLAB R2017b).
Let's say you plot 2 lines first, and then create a legend. Then you plot a 3rd line. That 3rd line will be added to your legend as 'data 1'.
Instead plot 3 lines, and then in your legend, label just the first 2 lines. The 3rd line will be omitted from the legend.
Hope this helps.
5 件のコメント
TheLast One
2019 年 6 月 1 日
Simplest solution :)
Orhan Soyuhos
2020 年 6 月 13 日
Thank you!
Another way to eliminate further plots from getting an automatic legend update (resuting in the 'data 1', 'data 2' etc. legend entries) was suggested by Phuc Bui on 2021-03-03 in a comment for the entry zoomPlot : Kelsey Bower (2021). zoomPlot
The most simple way to avoid "data1", "data2" is turning off the autoupdate property of the legend:
legend({'A','B'},'AutoUpdate','off')
@Jim Tonti Yes! Upvote his solution: legend({'A','B'},'AutoUpdate','off')
Gabriela Belicova
2022 年 5 月 13 日
Both very helpful, thank you so much !!!
Yasin Zamani
2019 年 9 月 25 日
編集済み: Yasin Zamani
2019 年 9 月 25 日
For example, suppose you want to skip the name of the first plot in the legend:
x = linspace(0, 2 * pi);
% sin(x)
h = plot(x, sin(x));
% the following line skip the name of the previous plot from the legend
h.Annotation.LegendInformation.IconDisplayStyle = 'off';
% cos(x)
plot(x, cos(x));
% legend
legend('cos');
4 件のコメント
Giulio Suzumura
2020 年 10 月 17 日
Tks. Best approach when uses 'hold on's and external functions.
Donald Liu
2021 年 7 月 21 日
Good solution, short and concise!
Carl Witthoft
2021 年 9 月 8 日
doesn't seem to work for a "fill" object
Soham Sinha
2022 年 5 月 11 日
Thanks
Boris Blagojevic
2021 年 6 月 23 日
An alternative approach: Prevent the legend from updating
First, plot the lines that you want to have labeled. Then, specify the legend and set
legend(....,'AutoUpdate','off')
then, plot the remaining lines
4 件のコメント
Riaan Ferreira
2021 年 8 月 10 日
This worked briliantly
Faezeh Ashouri
2022 年 4 月 10 日
Thanks!
Rik
2022 年 6 月 13 日
intersted
Dr.Jaber Aljuaidiyah
2024 年 8 月 20 日
This works nicely. Thanks pal
the cyclist
2011 年 1 月 25 日
8 投票
Each curve has a handle, which can be obtained from the properties. Use the form of legend that takes two arguments (handle and legend), and only use the handles of those curves that you want to show.
Dilshad Raihan
2015 年 10 月 26 日
編集済み: Dilshad Raihan
2015 年 10 月 26 日
2 投票
You can do this by first plotting the curves in an order so that the lines you don't want to be displayed in the legend comes in the end. That is, suppose you have N lines to be plotted but you dont want to display m of these in the legend. Then first plot the required N-m lines and then the remaining m. After that, turn the legend on, click on the legend and the "legend property editor" will be displayed. Go to the "more properties" option. You can see an entry titled "String" specified as a "1xN cell array". Click on the cell array icon and set the size as "1xN-m". Now, only the first N-m curves will be displayed in Legend.
1 件のコメント
Harish Pulluri
2016 年 9 月 26 日
Thnak you sir, for giving the solution
You can simply delete the last undesired entry by the following:
% assume you plotted some curves before this line and all of them are desired to be shown in the legend
hleg = legend('show');
plot(x,y) % you don't need this plot in the legend
hleg.String(end) = []; % delete the last legend entry of the very last plot
% continue plotting while copy and paste the previous line immediately after any plot you don't need in the legend
1 件のコメント
Amir Semnani
2021 年 6 月 9 日
Thanks. That worked for me (MATLAB 2017b) and it's very simple. Let's assume we have 8 datasets and we want to plot all of them, but only want to see the legend for dataset with even number.
x=ones(100,1)*(1:8); plot(x);ylim([0 9]); hleg = legend ('show'); hleg.String(1:2:end)=[];
Every time you plot, get the handle to the points or curves. Then pass only those that you want into legend. Here is a full demo:
lineSize = 2;
markerSize = 30;
% Define 3 data sets
x1 = [-1.9, 0.004, 1.94];
x2 = [-1.94, -0.23, 1.95];
x3 = [-1.92, .2, 1.93];
y1 = [13.885, 10.168, 14.235];
y2 = [9.3805, 5.2697, 9.3367];
y3 = [4.5262, 0.80904, 4.0889];
% Interpolate the 3 curves.
xFit = linspace(-2, 2, 500);
coefficients1 = polyfit(x1, y1, 2);
yFit1 = polyval(coefficients1, xFit);
coefficients2 = polyfit(x2, y2, 2);
yFit2 = polyval(coefficients2, xFit);
coefficients3 = polyfit(x3, y3, 2);
yFit3 = polyval(coefficients3, xFit);
% Plot the 3 data sets and their interpolated curves
handle1 = plot(x1, y1, 'r.', 'MarkerSize', markerSize);
hold on;
handle2 = plot(xFit, yFit1, 'r-', 'LineWidth', lineSize);
handle3 = plot(x2, y2, 'b.', 'MarkerSize', markerSize);
handle4 = plot(xFit, yFit2, 'b-', 'LineWidth', lineSize);
handle5 = plot(x3, y3, 'g.', 'MarkerSize', markerSize);
handle6 = plot(xFit, yFit3, 'g-', 'LineWidth', lineSize);
grid on;
% Have the legend only for the data, not the interpolated fit
% by passing in only the plot handles of the data.
legend([handle1, handle3, handle5], 'Data1', 'Data2', 'Data3', 'Location', 'north');
1 件のコメント
Allyce
2025 年 8 月 20 日
This was certainly an easy way to solve the issue - I was using two y-axis situation and had optional items in each axis - so I COULD have ordered the plot statements but much easier to set up the handles and then use the legend at the end. Thank you.
Akshay Ravindran
2015 年 11 月 26 日
0 投票
Why is it that this error keeps coming up?
<<

>>
3 件のコメント
Walter Roberson
2015 年 11 月 26 日
[z, x, c, v, b, n, m] looks like it might be intended as the list of "entries" to be annotated. Is it possible that those variables all hold column vectors instead of scalars, with the result that [z, x, c, v, b, n, m] is a 2 dimensional array?
Ajith Tom George
2016 年 11 月 17 日
If z,x,c etc are the handles, then remove the commas:
i.e. [z w c ...] and you are good to go!
Walter Roberson
2016 年 11 月 17 日
No, in each case where z w c etc are expressions that have no spaces in them, [z w c ...] is the same as [z, w, c, ...]
Spaces in expressions sometimes trigger parsing as if there were multiple expressions. For example:
[1 -2*x]
is considered two expressions, 1 and -2*x
Luke Marsden
2017 年 2 月 2 日
I am trying to do a similar thing using this line of code:
leg = legend([p4 RETU_Average activity1 Vulcanian1], 'Tilt', 'RETU Mean Amplitude', 'Activity', '"Vulcanian" Explosions', 'Location', 'northeast');
I am getting this error:
Error using matlab.graphics.chart.primitive.Line/horzcat
Cannot convert double value 23 to a handle
Error in p1_zoom_plot (line 93)
leg = legend([p4 RETU_Average, activity1 Vulcanian1], 'Tilt', 'RETU Mean Amplitude', 'Activity', '"Vulcanian" Explosions', 'Location', 'northeast');
4 件のコメント
Walter Roberson
2017 年 2 月 2 日
One of p4 RETU_Average activity1 Vulcanian1 contains the numeric value 23 instead of containing the handle to a graphics object.
The comma looks suspicious there.
I speculate that you might have passed in the values you are plotting rather than a copy of the handle that you got when you plotted them.
Luke Marsden
2017 年 2 月 3 日
Thanks for your reply Walter. With your help I have solved the problem.
23 is the first value in the vector named 'RETU_Average'. I was trying to pass the vector into the legend rather than the handle, which I created using this line of code.
p1 = plot (time, RETU_Average, 'LineWidth', 2);
New legend text for reference of anyone else who has made a similar mistake:
leg = legend([p4 p1 activity1 Vulcanian1], 'Tilt', 'RETU Mean Amplitude', 'Activity', '"Vulcanian" Explosions', 'Location', 'northeast');
Brent F
2021 年 8 月 10 日
Have you gotten this method of generating a legend using plot handles to work within a subplot?
Juan Carlos de Luna
2020 年 4 月 6 日
Select line in Plot Browser and type
set(get(get(gco,'Annotation'),'LegendInformation'),'IconDisplayStyle','off')
2 件のコメント
Bart Boonstra
2021 年 4 月 12 日
Thanks that worked for me!
Marya Sadki
2021 年 11 月 29 日
Me too thanks
If you plot multiple lines with the same plot command like this
h(1,:) = plot(rand(4,11),'r')
hold on
h(2,:) = plot(rand(4,11),'b')
and use
legend
on this, you get a 2x11 long legend
but you only want to highlight the first red and first blue line use this;
legend([h(1,1) h(2,1)],'red','blue')
This is mentioned in the documentation as;
legend(subset,___) only includes items in the legend for the data series listed in subset. Specify subset as a vector of graphics objects. You can specify subset before specifying the labels or with no other input arguments.
カテゴリ
ヘルプ センター および File Exchange で Data Distribution Plots についてさらに検索
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!


