why does simulink use the transfer function to simulate the step response?

Giuseppe Alfieri

2018 6 月 15

0 回答

11 ビュー (30 日間)

0 投票

2 件のコメント
なしを表示なしを非表示

Aditya Adhikary 2018 年 6 月 15 日

Both of these are separate blocks. Simulink does not "use" the transfer function, the model which you have designed or referred to here passes the output of the step function to the transfer function.

Giuseppe Alfieri 2018 年 6 月 15 日

I'm sorry but i didn't explain myself well. My question was because the output of transfer function's block is the step response in the time domain and not in Laplace one?

サインインしてコメントする。

サインインしてこの質問に回答する。

Follow Question