I have a hypothetical matrix say a =
1 2 3
2 4 5
3 5 6
in one command, how I can stack the first two columns vertically to have a=[1 2 3 2 4 5]'

3 件のコメント

Niveen El Zayat
Niveen El Zayat 2018 年 6 月 14 日
I got it I may use linear index so the answer is a(1:6)'
the cyclist
the cyclist 2018 年 6 月 14 日
You could make this an answer (rather than a comment on the question).
Niveen El Zayat
Niveen El Zayat 2018 年 6 月 14 日
I left it as a comment because i am not quite satisfied with this answer, I leave the space to some one give me a more generic answer fit any dimension

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Guillaume
Guillaume 2018 年 6 月 14 日
編集済み: Guillaume 2018 年 6 月 14 日

1 投票

As you've figured out for a 3xN matrix, a(1:6)' would work. For an arbitrary sized MxN matrix:
reshape(a(:, 1:2), [], 1)

1 件のコメント

Niveen El Zayat
Niveen El Zayat 2018 年 6 月 14 日
thanks, this is the answer I was looking for, because the above one is very simple hypothetical example my main code is in terms of large dimension and i did try the reshape command but i failed many time

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