Sum of base exponentials e

Good afternoon.

I hope you can support me in the following:

I have the following matrix 2 X 3

x1 = [8 2 9;
      2 3 2]

I want to do the following, I know that I take element by element of the first line of the matrix and that I do the sum:

AF = 5 * exp (8) + 5 * exp (2) + 5 * exp (9)

After that take the elements of the second line and as the sum does

AF = 5 * exp (2) + 5 * exp (3) + 5 * exp (2)

The first sum of the first line gives 55456.83 and the second sum of the second row gives 174.32

The matrix that I really have is 200 X 10 but the same will be done for those 200 lines.

I hope you help me because I've tried it several times and I could not.

Greetings.

Answer 1

[per isakson]

Matlab is clever

>> 5*sum( exp(x1), 2 )
ans =
   1.0e+04 *
   5.545715485358022
   0.017431824560524

[Ricardo Gutierrez]

Thank you very much!!!!!