Matrix Filling

1 回表示 (過去 30 日間)
Ahsan Khan
Ahsan Khan 2012 年 6 月 6 日
hi MATLABERS,
Im stuck at this problem. I want to make a matrix that does the following:
say i have the first row of the matrix [12 14 18]. now a get a random integer and it comes out to be 14. I want to store that 14 right under the 14 like so:
[12 14 18;0 14 0]
12 14 18
0 14 0
or
12 14 18
14
how can i do that. please help
  1 件のコメント
Sean de Wolski
Sean de Wolski 2012 年 6 月 6 日
And what do you want to do if the random integer is 59?

サインインしてコメントする。

採用された回答

Wayne King
Wayne King 2012 年 6 月 6 日
index = find(A(1,:) == 14);
A = cat(1,A,zeros(1,size(A,2)));
A(2,index) = 14;
Added after Sean's point -- if the integer is not present in the row, you'll just get a row of zeros.
index = find(A(1,:) == 59);
A = cat(1,A,zeros(1,size(A,2)));
A(2,index) = 59;
  2 件のコメント
Wayne King
Wayne King 2012 年 6 月 6 日
Sean has a very good point, note that in that case, the above will just fill with a row of zeros.
Ahsan Khan
Ahsan Khan 2012 年 6 月 6 日
thanks this works but how do i do this with a array of integers instead of just one.
ex predefined [1 2 3 4 5 6 7 8 9 10] is compared with a matrix [2 5 7;1 2 9 10;4 5 6] and the results should be as follows:
1 2 3 4 5 6 7 8 9 10
0 2 0 0 5 0 7 0 0 0
1 2 0 0 0 0 0 0 9
0 0 0 4 5 6 0 0 0

サインインしてコメントする。

その他の回答 (0 件)

カテゴリ

Help Center および File ExchangeCreating and Concatenating Matrices についてさらに検索

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by