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Assistance plotting radiation pattern

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Yuval
Yuval 2018 年 6 月 4 日
コメント済み: Star Strider 2018 年 6 月 5 日
I am trying to make a polar plot using the following code yet it doesn't come out as smooth as desired. I'd appreciate some further guidance:
P = [-65,-67,-66,-68.2,-67,-67,-66,-65,-63,-62,-52,-42,-41.5,-47.39,-60.5,-61.7,-63.35,-67,-65.2,-66.1,-71,-67,-67,-68,-65,-65];
A = [-180,-165,-150,-135,-120,-105,-90,-75,-60,-45,-30,-15,0,15,30,39,45,60,75,90,105,120,135,150,165,180];
G = P+10;
polarplot(A*pi/180,abs(G));

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Star Strider
Star Strider 2018 年 6 月 4 日
I’m not certain what result you want.
One option is to interpolate your data:
Ai = linspace(min(A), max(A), 360);
Gi = interp1(A, G, Ai, 'spline');
figure
polarplot(Ai*pi/180,abs(Gi));
You will need to experiment with that to get the appropriate result.
  8 件のコメント
Yuval
Yuval 2018 年 6 月 5 日
The attachment shows a regular Cartesian plot of the same P+41.5 vs. the angle. As you can see the gain is not always positive, as in the polar plot. The gain is expected to be negative too, especially when normalized wrt the maximum power, viz. -41.5. Was this more helpful? Any ideas?
Star Strider
Star Strider 2018 年 6 月 5 日
No ideas.
I was helping you with or original question, and plotting your vectors. Antenna theory is far from my areas of expertise.
The idea of ‘negative gain’ is essentially attenuation. This only makes sense if the units are dB, since negative in that sense simply means fractional.

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