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Why do i get "Array indices must be positive integers or logical values." error?

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Endrias
Endrias 2018 年 6 月 1 日
コメント済み: Endrias 2018 年 6 月 1 日
I keep getting this error from this function. Does anyone have an idea what is really happening?
%% SIMULATION
function [sys,x0,str,ts] = ctrl_sliding_mode(t,x,u,flag)
switch flag
case 0
[sys,x0,str,ts]=mdlInitializeSizes;
case 3
sys = mdlOutputs(t,x,u);
case {2,4,9}
sys=[];
otherwise
error(['Unhandled flag = ',num2str(flag)]);
end
function [sys,x0,str,ts]= mdlInitializeSizes
sizes = simsizes;
sizes.NumContStates = 0;
sizes.NumDiscStates = 0;
sizes.NumOutputs = 3;
sizes.NumInputs = 6;
sizes.DirFeedthrough = 1;
sizes.NumSampleTimes = 0;
sys = simsizes(sizes);
x0 = [];
str = [];
ts = [];
function sys = mdlOutputs(t,x,u)
lvp_ref = u(1); %REFERENCE SIGNAL
dlvp_ref = u(2);
lvp = u(3);
beta = u(4);
zeta = u(5);
dlvp = u(6);
eta = 0.2;
c = 10;
e = lvp - lvp_ref;
de = dlvp - dlvp_ref;
s = c*e;
M=2;
if M==1
ut = 1/(c*beta*lvp^zeta)*(-eta*sign(s) + c*dlvp_ref);
elseif M==2 %Saturated function
delta=0.2;
kk = 1/delta;
if abs(s)>delta
sats = sign(s);
else
sats=kk*s;
end
ut = 1/(c*beta*lvp^zeta)*(-eta*sats(s) + c*dlvp_ref);
end
sys(1) = ut;
sys(2)= e;
sys(3) = de;
  7 件のコメント
Endrias
Endrias 2018 年 6 月 1 日
@Sandro Sats(s) is a function like sign(x) i.e. peicewise. And when i choose e.g. M = 1, i get the next error eventhough i see that a vector of length 3 is passing put as an output...
An error occurred while running the simulation and the simulation was terminated Caused by: Output returned by S-function 'ctrl_sliding_mode' in 'sim_sliding_mode/S-Function' during flag=3 call must be a real vector of length 3;
Sandro Lecci
Sandro Lecci 2018 年 6 月 1 日
What is supposed to do the function sats? According to your if loop when M==2, sats is a variable that stores either the sign of s or the multiplication between s and kk (variables as well).

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Walter Roberson
Walter Roberson 2018 年 6 月 1 日
s = c*e but c=10 and e = lvp - lvp_ref but lvp_ref is scalar and lvp = u(3) . So lvp is scalar and so e is scalar and so s is scalar. That would make sign(s) a scalar, and with kk being scalar, kk*s would be a scalar. So sats is a scalar. But you have sats(s) in the ut calculation, which is an indexing request.
  1 件のコメント
Endrias
Endrias 2018 年 6 月 1 日
You are prefectly right @Walter. It works now ... thank you very much all!!!

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