Code printing double line

num1 =input('Enter your 1st number: ');
num2 =input('Enter your 2nd number: ');

 %returns an 1-by-num2 matrix of zeros
 PerfectNumber= zeros(1,num2);

 for pp = num1:num2 % pp = Potential Perfect number, variable for the range 
    if true
    end
    pd = 1:pp-1;
    %test all potential numbers up to pp-1 because of the definition of a perfect number.
    %potential divisors, named 'pd' in the code

    if (sum(pd(mod(pp,pd) == 0)) == pp)
        %mod(pp,pd) returns the remainder after dividing pp by pd. 
        %If a number is a divisor, the remainder is 0, so mod return zero.
        %check if the sum of all divisors = pp
        PerfectNumber(pp) = pp;
        %it have found a perfect number and store this number in a variable 'output' at the pp'th position
           if false
          else PerfectNumber (PerfectNumber == 0) = []; 
          %all positions where output is 0 are replaced by the empty matrix []
            fprintf ('\nThe Perfect Numbers are : %d', PerfectNumber);
          %And it will print out the name line + the perfect number
        end
    %After this loop we have the perfect numbers at the position of the perfect numbers.
    end
end
fprintf ('\nThe program ends here, Good bye %s !',un);
    %to inform the user that the program has ended or when the entry is invalid it end the program.
  end

And my out put would be

 Enter your 1st number: 1
 Enter your 2nd number: 50

 The Perfect Numbers are : 6
 The Perfect Numbers are : 6
 The Perfect Numbers are : 28
 The program ends here, Good bye  !>>

What should i do to my code so that it only print the line "The Perfect Numbers are : 6" once and not double like this.

[Paolo]

Try changing:

 PerfectNumber(pp) = pp;

to

 PerfectNumber = pp;

[Laeya]

Thank you so much ! yours work well too !

Answer 1

[Rishabh Rathore]

What is happening is that you are actually printing the whole vector instead of the latest 'perfect Number'.

Make your print line look like below.

fprintf ('\nThe Perfect Numbers are : %d', PerfectNumber(end));

[Laeya]

Thank you so much for the help! been stuck on this for so long!!

[Paolo]

The question here is whether you need all the numbers in PerfectNumber in a different stage of the code. If you do not, there is no reason for you to have

 PerfectNumber(pp) = pp;

as I mentioned in the comment.