points clusters in 3-D

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Subarna Giri
Subarna Giri 2018 年 5 月 14 日
コメント済み: Subarna Giri 2018 年 5 月 14 日
Hi, there: I have 4000 points to be plotted around two centers with standard deviation 1 and mean 0. The center of the points must be P(x1,y1,z1) and Q(x2,y2,z2). Anybody have idea how to do this? Please help me. Thank you.
Regards' S.Giri

回答 (1 件)

Walter Roberson
Walter Roberson 2018 年 5 月 14 日
cluster_P = bsxfun(@plus, [x1, y1, z1], randn(4000,3));
scatter3(cluster_P(:,1), cluster_P(:,2), cluster_P(:,3));
However, you need to clarify what it means to have standard deviation 1 and mean 0 when there are three dimensions to consider. Is the idea that the radius should be determined by randn() and that random angles should be taken?
  3 件のコメント
Walter Roberson
Walter Roberson 2018 年 5 月 14 日
Are the two spheres to be of specific radius? Is the radius of the sphere to be determined randomly but after that the positions of the 4000 points should be equally distributed? Is each point's distance from its center to be set randomly?
What property of the points is to have standard deviation 1 and mean 0 ?
Subarna Giri
Subarna Giri 2018 年 5 月 14 日
The standard deviation determine the radius. Mean 0 tells that points distributed equally in positive and negative direction. No.of points in positive direction must be equal to points in negative directions. We can define radius but it must satisfy given conditions.

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