How to add a polygon to UIAxes in appdesigner?

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Kyle Millar
Kyle Millar 2018 年 5 月 10 日
コメント済み: Kyle Millar 2018 年 5 月 15 日
I currently can create a rectangle in the UIAxes with this code:
rect = rectangle(app.UIAxes, 'Position', [0 26 .13 98], 'FaceColor', 'r', 'EdgeColor', 'r');
but what if I want to define where each corner is in the axes. As in, not a rectangle or any other standard shape. I have looked into the patch object, but this code does not work:
X = [0 0 .13 .13]
Y = [26 124 124 26]
shape = patch(app.UIAxes, app.swathX, app.swathY, 'r');
How can I do that with UIAxes?
  2 件のコメント
Greg
Greg 2018 年 5 月 11 日
編集済み: Greg 2018 年 5 月 11 日
"but this code does not work:"
How so? What does it do? How is that different from what you expect? Does it throw an error? Post the error if it does.
I would hope
X = [0 0 .13 .13]
Y = [26 124 124 26]
shape = patch(app.UIAxes, app.swathX, app.swathY, 'r');
throws some form of unknown variable/property error, as you define X and Y but use swathX and swathY.
Kyle Millar
Kyle Millar 2018 年 5 月 12 日
In the third line, it should say X and Y. I forgot to change the variable names in the question. This is the error I get:
Error using patch
While setting property 'Parent' of class 'Patch':
Functionality not supported with UIAxes. For more information, see Graphics Support in App Designer.

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回答 (1 件)

Greg
Greg 2018 年 5 月 11 日
ps = polyshape([0,0,.13,.13],[26,124,124,26]); % This is still a rectangle though...
pg = plot(uiaxes,ps);
  9 件のコメント
Sean de Wolski
Sean de Wolski 2018 年 5 月 15 日
Is upgrading not an option? App designer is under active development so it gets a lot of new features with each release.
Kyle Millar
Kyle Millar 2018 年 5 月 15 日
I'm not sure. I don't think so. It is a school license that has not ran out yet, but I just graduated. I don't know if I can upgrade it anymore.

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