Hi,i'm fairly new to all this, but as the title say i need help to make a point plot from my data. So i have a [M N] Matrix (my test data is 7x15, but it need to work with any size matrix),
i want to have so it look like this.: https://www.google.dk/search?q=scatterplot&source=lnms&tbm=isch&sa=X&ved=0ahUKEwj27tGe7vDaAhXTxKYKHabqBAsQ_AUICigB&biw=1366&bih=637#imgrc=hjPIB_OYmEMk7M: but i can't make it work with a unknown size matrix. I have tried with the in-build scatterplot function (isn't it the best function to use in this case) I have also tried with gplotmatrix but it's a bit more complex..
Thank you in advance, sincerely
Christian

4 件のコメント

Ameer Hamza
Ameer Hamza 2018 年 5 月 6 日
This is just one variable. For scatter, you will need two variables. How do you decide the location of each point from this matrix.
Christian Jensen
Christian Jensen 2018 年 5 月 6 日
編集済み: per isakson 2018 年 5 月 6 日
I were thinking that the x value would be equal the column value if that make any sense. an example: if I had the matrix
[1,1,1;2,2,2;3,3,3]
then the coordinates I would have to plot would be
for column 1: (1,1), (1,2) & (1,3)
for column 2: (2,1), (2,2) & (2,3)
for column 3: (3,1), (3,2) & (3,3)
Ameer Hamza
Ameer Hamza 2018 年 5 月 6 日
Do you mean column value or row value? Look at my answer below. It takes column number as x value.
Christian Jensen
Christian Jensen 2018 年 5 月 6 日
column value, going to try it out, thanks !

サインインしてコメントする。

 採用された回答

Ameer Hamza
Ameer Hamza 2018 年 5 月 6 日

1 投票

As you mentioned in the comment, you can do it as follow
xData = ones(size(data)).*[1:size(data,2)]; % create x matrix with same column number
scatter(xData(:), data(:));
here data is the name of your m*n matrix.

2 件のコメント

Christian Jensen
Christian Jensen 2018 年 5 月 6 日
YES! it worked been trying for almost two days to make it work, thanks :-D
Ameer Hamza
Ameer Hamza 2018 年 5 月 6 日
Happy that it helped. You are welcome.

サインインしてコメントする。

その他の回答 (0 件)

カテゴリ

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by