put smaller matrix in bigger matrix

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Andrea
Andrea 2012 年 5 月 30 日
Hello I have row=[1 2 5 4 3 6] and column=[5 7 3 4 8 14]. I want to select and put each Q(row,column) in a new data. for example Q(row(1),column(1)), Q(row(2),column(2)), and Q(row(3), column(3)), .. . I want to put these Q in a new matrix P. Can anybody help me? something like this that does not work: P=Q((1:row),(1:column)) or P=Q(row,column)
  2 件のコメント
Rahul
Rahul 2012 年 5 月 30 日
How do you want output
q= 1 5
2 7
5 3
4 4
3 8
6 14
Is this how your output q should look like? give an example of your output..
Andrea
Andrea 2012 年 5 月 30 日
No. These are the indicators of row and col. for example Q(row(1),column(1))=10, Q(row(2),column(2))=25 , and Q(row(3), column(3))=12 and ....
I want to to put them in a matrix P=zeros(size(Q)). in the way their arrangement will not change.
please see this example:
Q =
1 2 3 4 5 6
3 2 1 6 5 4
0 1 10 5 5 1
8 7 9 8 1 0
row = [2 3];
col= [ 4 5 6];
P =
6 5 4 0 0 0
5 5 1 0 0 0
0 0 0 0 0 0
0 0 0 0 0 0
and then, I want to select another sub-matrix (with different size such as 1*2) and put it right next to the first part in Matrix P.

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採用された回答

Andrei Bobrov
Andrei Bobrov 2012 年 5 月 30 日
eg:
Q = randi(456,10,15);
row=[1 2 5 4 3 6];
column=[5 7 3 4 8 14];
P = Q(sub2ind(size(Q),row,column));
EDIT
p = Q(row,column);
P = zeros(size(Q));
P(1:numel(row),1:numel(column)) = p;
  3 件のコメント
Andrea
Andrea 2012 年 5 月 30 日
Just one issue occurs. I need matrix p to have Q(row(1),column(1)), Q(row(1),column(1)), Q(row(2),column(2)), Q(row(3),column(3)), Q(row(4),column(4)), Q(row(5),column(5)), and Q(row(6),column(6)). But what (p = Q(row,column);) give me is a 6*6 matrix in this way Q(row(1),column(1)), Q(row(1),column(2)), Q(row(1),column(3)), Q(row(1),column(4)), and..... How can solve this problem?
Andrei Bobrov
Andrei Bobrov 2012 年 5 月 31 日
Hi Andrea! Please see my answer (befor 'EDIT')

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