Increase determine step size

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Kostas Tsakos
Kostas Tsakos 2018 年 4 月 27 日
回答済み: Image Analyst 2022 年 8 月 9 日
Hello I want to have this steps (1,2,4,6,8).
How can I do it to be in the form of, for example:
n=5
n=1:2:((2*n)-2)

回答 (2 件)

Walter Roberson
Walter Roberson 2018 年 4 月 27 日
t = 1:5; steps = 3+(-53/12+(71/24+(-7/12+(1/24)*t).*t).*t).*t
I would suggest that you reconsider your task. It would, for example, have been much easier as
t = 1:5; steps = [1, (t(2:end)-1)*2]
  2 件のコメント
Walter Roberson
Walter Roberson 2018 年 4 月 27 日
You cannot get that.
You can use (t-1)*2 + (t==1) or other ways of making an exception for the first value, but the 1 entry cannot be handled with a plain increment.
Now, if you had wanted [1, 2, 4, 8] without the 6 then that would have been easy: t = 1:4; 2.^(t-1)

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Image Analyst
Image Analyst 2022 年 8 月 9 日
Try this:
n = 5;
n = [1,2:2:((2*n)-2)]
n = 1×5
1 2 4 6 8

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