date format
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Hello All,
I have a data in a file with yyyy.mm.dd format. I want to read it and write it in a new file. This data is one column in the matrix of the data. any suggestions?
thanks
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回答 (2 件)
Fangjun Jiang
2011 年 3 月 25 日
help datenum, datestr, for example datenum('2000.05.19','yyyy.mm.dd')
3 件のコメント
Fangjun Jiang
2011 年 3 月 25 日
Can you provide an example of your data (a small sample maybe) and what end result you expect?
Jan
2011 年 3 月 25 日
@Ravi: DATENUM is the best method. Please explain with more details what "does not work" mean.
Walter Roberson
2011 年 3 月 25 日
Do you just need to copy it to the new file, or do you need to change the format of the date as you go?
If you need to change the format beyond just re-arranging the parts (e.g., moving the year to the end) then datenum() is the way to go.
If you need to change the format with just re-arranging the parts and the parts are fixed length, then array indexing can be much more efficient.
If you are just copying without any re-arranging, then the biggest trick is in knowing how to output cell strings.
What output format do you need? Just a single column of dates? If so then sometimes xlswrite() is the easiest way: on Windows machines that have Excel installed it can write cell arrays into columns of output. If you are not using Windows or do not have Excel installed, then the easiest way to do the output can vary according to exactly what you want to output.
2 件のコメント
Walter Roberson
2011 年 3 月 26 日
The easiest thing to do with that column is read it as a string, '%s' format, and write it with a %s format to the output file. If, that is, you do not need to use the data in your calculations.
If you need to use the date in your calculations and so have variables for the parts, then use
fprintf('%04d.%02d.%02d', year, month, day)
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