フィルターのクリア

Running two counter in one for statement

6 ビュー (過去 30 日間)
Rich Cavanaugh
Rich Cavanaugh 2018 年 4 月 12 日
コメント済み: Rich Cavanaugh 2018 年 4 月 12 日
Hello, I am trying to wright a for loop that has two counters that run counter to each other.
here is one of my attempts limiting the size of .rows and .cols to 3 in reality those values will be much larger
for (i = 1:3)
for(j = 3:-1:1)
handles.checkerDR{i}=...
handles.([handles.rows{i} handles.cols{j}]).String;
end
end
what I would like is checkerDR to be a cell array of
checkerDR{1}=handles.([handles.rows{1} handles.cols{3}).String;
checkerDR{2}=handles.([handles.rows{2} handles.cols{2}).String;
checkerDR{3}=handles.([handles.rows{3} handles.cols{1}).String;
so on and so forth does anyone have any ideas? i have been trying different iterations for a while and im not sure how to get this to work Thanks in advance

採用された回答

Geoff Hayes
Geoff Hayes 2018 年 4 月 12 日
Rich - try using just one for loop
maxIter = 3;
for k=1:maxIter
handles.checkerDR{k}=...
handles.([handles.rows{k} handles.cols{maxIter - k + 1}]).String;
end
  1 件のコメント
Rich Cavanaugh
Rich Cavanaugh 2018 年 4 月 12 日
that works perfectly. Thanks a million

サインインしてコメントする。

その他の回答 (0 件)

カテゴリ

Help Center および File ExchangeMATLAB についてさらに検索

タグ

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by