How can i get multiple values in fprintf?

So i have 'n' lots of integers every time I run the script. My code displays my fprintf n times...
fprintf('I have numbers: %d \n',numbers)
Is there a way to display all the 'n' numbers in the same line rather than repeating?
So I have if n=4
I have numbers: 1
I have numbers: 2
I have numbers: 3
I have numbers: 4
and I want:
I have numbers: 1,2,3,4
If I knew n i could put multiple %d 's in the fprintf.... but my n changes every time...

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KSSV
KSSV 2018 年 4 月 11 日

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n = [1, 2, 3];
fprintf('I have numbers: %s\n', sprintf('%d ', n))

3 件のコメント

JJ
JJ 2018 年 4 月 11 日
Thanks, I knew it must be something simple but just couldn't seem to think of it
JJ
JJ 2018 年 4 月 11 日
Ok so my numbers are being calculated and change each time so like:
n=10
number=2*n
fprintf('I have numbers: %d \n',numbers)
JJ
JJ 2018 年 4 月 11 日
Its ok I have it now thanks

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2018 年 4 月 11 日

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