How to take first character of Alphabet

    Hi,

    I want to take the first character of the first alphabet from string contain mixed data,

    I have below cell array:

    data:
    {'VA00K100E4TOO';'ZVA00K100E4TOO';'VZA00K100E6TO';'VB00K100E4TOO';'VP00K50E4T4O';'ZVG00K100E4TOO';'VF00K40E4T5O'}

    1. I want to first letter of alphabet, ignore if first or second characters are Z or V.

I use below command to extract alphabets from each string,

data(isstrprop(data,'alpha'))

but later I am unable to avoid if the first or second character is Z or V,

    my desired output:

    A
    A
    A
    B
    P
    G
    F

Answer 1

[M]

One way to do it :

regexpi(data,'[a-u]','match','once')
ans =

7×1 cell array

    {'A'}
    {'A'}
    {'A'}
    {'B'}
    {'P'}
    {'G'}
    {'F'}

[Mekala balaji]

Sir,

it works,but may I know how does it work? if I want avoide other alphabets (like if first or second letter is N or T etc), and the very first alphabet,

[M]

To write a more generic version of my previous answer, you can use something like:

Alphabet = '[ABCDEFGHIJKLMNOPQRSTUVWXYZ]';

% choose which letters you want to suppress

lettersToRemove=['Z' 'V'];

% remove them from your alphabet list:

for i=1:numel(lettersToRemove)
    Alphabet(Alphabet==lettersToRemove(i))=[];
end

% keep only the first letter of your alphabet list:

regexpi(data,Alphabet,'match','once')
ans =

7×1 cell array

    {'A'}
    {'A'}
    {'A'}
    {'B'}
    {'P'}
    {'G'}
    {'F'}

% Now, suppose you want to remove V and G:

lettersToRemove=['V' 'G'];  
for i=1:numel(lettersToRemove)
  Alphabet(Alphabet==lettersToRemove(i))=[];
end
regexpi(data,Alphabet,'match','once')