hello , i want to remove the repeated values in vector without using Unique function

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Ashraf Hisham
Ashraf Hisham 2018 年 4 月 1 日
コメント済み: Walter Roberson 2018 年 4 月 1 日
if a = [1 1 2 2 3 3 1] i want the result to be a=[1 2 3] thanks

回答 (2 件)

Birdman
Birdman 2018 年 4 月 1 日
A = [1 1 2 2 3 3 1]
[val,idx]=sort(A)
idx=A(idx(1:end-1))==A(idx(2:end))
val(idx)=[] % take it as new A vector
  4 件のコメント
Ashraf Hisham
Ashraf Hisham 2018 年 4 月 1 日
actually the question of my exam needs to do with for loop :(
Walter Roberson
Walter Roberson 2018 年 4 月 1 日
Okay, suppose you are examining element 4 out of 7, and you need to delete it because it is the same as something earlier. So you x(4)=[] . Now x is length 6. But your for loop still goes to 7.
You need to use one of these techniques:
  • keep a record of which items are to be deleted and delete them all at the same time after you have done your loops; or
  • start at the end and move to the beginning so that when the array gets shorter that does not matter because you are only going to look at earlier elements. (You might need to adjust this strategy for your situation.)

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Walter Roberson
Walter Roberson 2018 年 4 月 1 日
find(sparse(a,ones(size(a)),1))
Note: only works for positive integers.

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