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how to use nested for loop by grabbing one column and subtracting another column.

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tonyrodriguez
tonyrodriguez 2018 年 3 月 29 日
編集済み: Roger Stafford 2018 年 3 月 29 日
so i have this huge file that is 1478 by 1236 matrix and i want to calculate the xslope and yslope as follows
  1 件のコメント
tonyrodriguez
tonyrodriguez 2018 年 3 月 29 日
so far i have this
cellsize = 9.47733915533982;
xslope = zeros(1478,1236);
n = length(xslope);
for i = 1:n for j = 1:1:n
xslope(i,j) = ( z(i,j+1)-z(i,j) )/cellsize;
end
end
xslope
it tells me i have a matrix dismension.. can someone help me fix this or tell me how i can do it?

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回答 (1 件)

Roger Stafford
Roger Stafford 2018 年 3 月 29 日
編集済み: Roger Stafford 2018 年 3 月 29 日
Your n value will be 1478, but in z(i,j+1) you have allowed the j+1 index to get as large as 1479 because you have "for j=1:1:n" and its maximum value should be only 1236. Hence the error message. You need to do
[n,m] = size(z)
and
for j = 1:m-1

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