making a rotation matrix

2 ビュー (過去 30 日間)
Jeroen
Jeroen 2012 年 5 月 22 日
{
clc
b = [cos((angle/180)*pi) -sin((angle/180)*pi);sin((angle/180)*pi) cos((angle/180)*pi)];
for i = 1:1:size(nr_out,1)
a = [nr_out(i,1);nr_out(i,2)];
c = b*a;
rotatie(i) = [c(1,1) c(2,1)];
end
}
Hello I am trying to make a rotation matrix. To do that i multiply the x and y from a file with the rotation matrix [cos(a) -sin(a); sin(a) cos(a)] What I want is that the matrix 'rotatie' grows with in the first column the x value ( c(1,1)) and in the second column the y-value(c(2,1)).
The error it gives is this: In an assignment A(I) = B, the number of elements in B and I must be the same.
Gr jeroen

回答 (1 件)

Honglei Chen
Honglei Chen 2012 年 5 月 22 日
You need to do something like
rotatie(i,:) = [c(1,1) c(2,1)];
But if I understand your question correctly, you can do it without a loop
rotatie = (b*nr_out.').'
  2 件のコメント
Jeroen
Jeroen 2012 年 5 月 22 日
I am sorry I forgot to tell that the matrix nr_out is a matrix that consist of x,y,z,ex,ey,ez and I have to rotate the whole matrix with 20.58 degree in the xy-plane with their energies.
Honglei Chen
Honglei Chen 2012 年 5 月 22 日
Then you can just use the first solution, use rotatie(i,:) instead of rotatie(i)

サインインしてコメントする。

カテゴリ

Help Center および File ExchangeResizing and Reshaping Matrices についてさらに検索

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by