making a rotation matrix
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{
clc
b = [cos((angle/180)*pi) -sin((angle/180)*pi);sin((angle/180)*pi) cos((angle/180)*pi)];
for i = 1:1:size(nr_out,1)
a = [nr_out(i,1);nr_out(i,2)];
c = b*a;
rotatie(i) = [c(1,1) c(2,1)];
end
}
Hello I am trying to make a rotation matrix. To do that i multiply the x and y from a file with the rotation matrix [cos(a) -sin(a); sin(a) cos(a)] What I want is that the matrix 'rotatie' grows with in the first column the x value ( c(1,1)) and in the second column the y-value(c(2,1)).
The error it gives is this: In an assignment A(I) = B, the number of elements in B and I must be the same.
Gr jeroen
0 件のコメント
回答 (1 件)
Honglei Chen
2012 年 5 月 22 日
You need to do something like
rotatie(i,:) = [c(1,1) c(2,1)];
But if I understand your question correctly, you can do it without a loop
rotatie = (b*nr_out.').'
2 件のコメント
Honglei Chen
2012 年 5 月 22 日
Then you can just use the first solution, use rotatie(i,:) instead of rotatie(i)
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