how to convert decimal to binary ?

I have vector of integer values : y = [ 1 2 3 4 5 ... 998 999 1000 ] , how can i generate binary random numbers with the same length for lower and upper of vector y ( i.e the binary value of 1000 is (0 0 0 1 0 1 1 1 1 1), and the binary value of 2 is ( 1 0 0 0 0 0 0 0 0 0 ) and so on .. This is the code y = [ 1 : 1000 ]; empty.value = []; out=repmat(empty.value,5,1);

for i = 1 : 5 % i want 5 binary numbers within the range 1 to 1000 and must be all the same length of bits a = randi(1000); b = de2bi(a); out(i).value = b ; end %% the results are different in number of bits {[1,1,1,1,1,1];[1,1,0,1,0,1,0,0,1];[1,1,1,1,0,1];[0,1,0,1,1,1,1,1,1];[0,1,0,1,1,1,1,1,0,1]}

Answer 1

[Stephen23]

>> dec2bin(randi([1,1000],5,1),10)
ans =
1101100000
1000010111
1100010100
0000100001
1110110000

And to convert to numeric simply subtract '0':

dec2bin(...)-'0'

[Ameer Kadhim]

Thank you so much...

[Ameer Kadhim]

but this output is char i want it integer in order to convert it to decimal later

[Andrei Bobrov]

dec2bin(randi([1,1000],5,1),10)-'0'

[Ameer Kadhim]

thank you very very very much...

[Stephen23]

@Ameer Kadhim: I hope that it helps. Remember to accept the answer that helped you most to resolve your question.

[Ameer Kadhim]

Thank you Stephen Cobeldick very much.. i accept your answer

[Birdman]

I deleted mine then since this answer solves your problem.

[Ameer Kadhim]

your answer do not solve my problem and i asked several times... thank you dir , i am sorry....

[Ameer Kadhim]

@Stephen Cobeldick your answer not correct too .. see v = bi2de(dec2bin(randi([1,1000],1,1),10)-'0') v =

        1013
i not want v greater than 1000 . ok (v must be less than 1000)

[Wubie Engdew]

>> dec2bin(randi([1,1000],5,1),10)

ans =

5×10 char array

'1100101111'

'1110001010'

'0001111111'

'1110010010'

'1001111001'