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how can I filter the nth character from categorical?

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Aletta Wilbrink
Aletta Wilbrink 2018 年 3 月 19 日
回答済み: Peter Perkins 2018 年 3 月 23 日
i have a categorical value a, looks like:
a = 888-2018-02160001
Now I want the 10th and 11th character, the '02'.
I already tried a(10:11), but that doesn't work, because the length of a is 1. Also when I try string(a), the length is still 1
How can I filter these characters from a categorical?

採用された回答

Birdman
Birdman 2018 年 3 月 19 日
>>a = '888-2018-02160001'
a(10:11)
ans =
'02'
  3 件のコメント
Birdman
Birdman 2018 年 3 月 19 日
編集済み: Birdman 2018 年 3 月 19 日
What does your variable look like? If it is in string form, then simply convert them to char by typing
char(a)
and then extract 10th and 11th characters at all rows as
a(:,10:11)
Aletta Wilbrink
Aletta Wilbrink 2018 年 3 月 19 日
That works, thanks!

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その他の回答 (1 件)

Peter Perkins
Peter Perkins 2018 年 3 月 23 日
If you have a categorical variable, as in the categorical data type, then it sounds like you want to work with the category names. Converting the entire (large) categorical array will be very inefficient in terms of memory. probably the easiest thing to do is to make a copy, modify the copy's category names using renamecats, and you're done.
Not enough information to go to know if that's what you want.

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