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How to generate a joint probability matrix from a data matrix

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alpedhuez
alpedhuez 2018 年 3 月 17 日
回答済み: Roger Stafford 2018 年 3 月 17 日
Suppose I have a data matrix
Sample# X Y
1 1 1
2 1 2
3 1 1
Then I want to generate a joint prob matrix
X Y Prob
1 1 0.67
1 2 0.33
Please advise.

採用された回答

Michelangelo Ricciulli
Michelangelo Ricciulli 2018 年 3 月 17 日
編集済み: Michelangelo Ricciulli 2018 年 3 月 17 日
Hi, A simple way to get the joint probability matrix for two dimension is using the hist3 function, (read the documentation here ). Let's call your initial matrix nXY
nXY=[1 1 1;
2 1 2;
3 1 1]
You will need only the last two columns to count the occurrence of each combination of X and Y (So, we can use nXY(:,2:3)). Also, you need to define a cell array containing all the possible X values and Y values. In this case, just 1 and 2, so:
Xv=[1 2];
Yv=[1 2];
values={Xv Yv};
count=hist3(nXY(:,2:3),'ctrs',values); %first count the values
p=count/sum(sum(count)); % then divide by the sum on all matrix value to get probability
You will get in the estimated joint probabilities in the matrix p. You'll just need to rewrite them in the form you need.

その他の回答 (1 件)

Roger Stafford
Roger Stafford 2018 年 3 月 17 日
Call the data matrix D. Then the two columns of D(:,2:3) are X and Y.
XY = sortrows(D(:,2:3));
F = find( [true,any(XY(1:end-1,:)~=XY(2:end,:),2),true] );
J = [XY(F(1:end-1),2:3),diff(F)/(F(end)-1)]; % <-- Joint probabilities in column 3
Columns 1 and 2 of J will contain unique X Y pairs.

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