Multiplication of each column with each other with a condition

I have a table of 4x11. And I would like to multiply each column with each other and save the results to another table. for example: firstresults = table(1,1)*table(1,2)*table(1,3)...*table(1,11). When columns reach 11, I want my loop to start calculate it for second rows. secondresults = table(2,1)*table(2,2)..table(2,11). I am trying to do that with for loop but I just can't. Is it something like that?

secondresults(ii,j) = table(ii,j) * table(ii,j+1). 
if j <= 14,
ii = ii+1 Got stuck for hours. Thanks in advance.

[Adam]

If you have an array you can just do

results = prod( table, 2 );

to get all the results in a single variable. I don't know off-hand how you would do this if you have an actual table, but if you do then you just overwrote the 'table' function with your variable name too which is not good at all.

Answer 1

[Bob Thompson]

You could accomplish this fairly easily using one or two for loops, depending on your style. The only loop you really require is a loop to run through the rows. For the columns, you can include a loop if you would like, or have a variable number of rows, or you can simply define it ahead of time.

for k = 1:size(table,1) % Run through all rows
   results(k) = table(k,1)*table(k,2)*...*table(k,11) % This is the manual entry version, you need to enter all the columns individually.
end

for k = 1:size(table,1) % Again, all rows
   results(k) = 1; % You need to pre-initialize your results for this one
   for h = 1:size(table,2) % Run through all columns
      results(k) = results(k)*table(k,j) % Multiply columns of row k together. This is the automated version, but added complexity could potentially produce errors
   end
end