Split a double array by zero and store in a column matrix

1 回表示 (過去 30 日間)
Dhanushka Sandaruwan
Dhanushka Sandaruwan 2018 年 3 月 3 日
This is my code. But it gives the error 'Dimensions of matrices being concatenated are not consistent'.
My expected output is;
2 5 6 8 9
11 13 14 18
3 7 15 19 20
Please help!
Routes=[0 2 5 6 8 9 0 11 13 14 18 0 3 7 15 19 20 0];
Display=[];
Current_Cluster=[];
for i=2:length(Routes)
if Routes(i) ~=0
Current_Cluster=[Current_Cluster Routes(i)];
else
Display=[Display ; Current_Cluster];
Current_Cluster=[];
end
end
disp('Çulsters are');
Display

採用された回答

Walter Roberson
Walter Roberson 2018 年 3 月 3 日
You cannot create a numeric matrix with that output. Your second row only has four numeric entries whereas the first and third have 5 entries.
You can create a text output that would display to look like what you want, but you cannot do it numerically.
You can create a cell array with one number per cell, and with empty cells, but you might not like the display.
  1 件のコメント
Dhanushka Sandaruwan
Dhanushka Sandaruwan 2018 年 3 月 4 日
Thanks Roberson. According to your comment I changed the code as follows.
Routes=[0 2 5 6 8 9 0 11 13 14 18 0 3 7 15 19 20 0];
Display={};
Current_Cluster=[];
for i=2:length(Routes)
if Routes(i) ~=0
Current_Cluster=[Current_Cluster Routes(i)];
else
Display=[Display , num2str(Current_Cluster)];
Current_Cluster=[];
end
end
disp('Culsters are');
Display'
Now it is working as I want but can't understand how it works. Anyway thanks a lot.

サインインしてコメントする。

その他の回答 (0 件)

カテゴリ

Help Center および File ExchangeStructures についてさらに検索

タグ

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by